获取函数地址并调用函数

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最简单的直接测试

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#include <iostream>

using namespace std;

void test() {
    cout << "DONE!" << endl;
}

int main() {
    cout << test << endl;
    void (*myCALL)();
    myCALL = test;
    (*myCALL)();
    cout << *myCALL << endl;
    return 0;
}

从数组中获取地址并调用

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#include <iostream>
#include <vector>

using namespace std;

void test() {
    cout << "DONE!" << endl;
}

void callFunc(int x) {
    void (*pro)();
    pro = (void (*)()) x;
    (*pro)();
}

int main() {
    vector<int> address;
    address.push_back(int(test));
    cout << test << endl;
    callFunc(address[0]);
    return 0;
}

获取类成员函数地址并调用$^{1}$

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#include <iostream>

using namespace std;

class A
{
public:
    void fn() { 
        cout << "myCallFunc is Done~" << endl; 
    }
};

template<typename dst_type, typename src_type>
dst_type pointer_cast(src_type src)
{
    return *static_cast<dst_type*>(static_cast<void*>(&src));
}

long getAddress(decltype (&A::fn) x)
{
    void* ptr = pointer_cast<void*>(x);
    return (long)ptr;
}

void callFunc(long x) {
    void (*pro)();
    pro = (void(*)()) x;
    (*pro)();
}

int main(void)
{
    long address = getAddress(&A::fn);
    callFunc(address);
    return 0;
}

对应的函数模板与使用方法

getAddress

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template<typename dst_type, typename src_type>
dst_type getAddress(src_type x)
{
    void* ptr = pointer_cast<void*>(x);
    return (dst_type)ptr;
}
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long address = (long)getAddress<void*>(&FuncFlowT::funcA);

callFunc

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template<typename src_type>
void callFunc(src_type x) {
    void (*pro)();
    pro = (void(*)()) x;
    (*pro)();
}
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callFunc<long>(address);

Reference

  1. https://www.cnblogs.com/memset/p/get_member_function_address_cpp.html

  2. https://bbs.csdn.net/topics/80149694



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